$$(x-2)^2+4 = 0$$
Answer
$$ \begin{matrix}x_1 = 2+2i & x_2 = 2-2i \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x-2)^2+4 &= 0&& \text{simplify left side} \\[1 em]x^2-4x+4+4 &= 0&& \\[1 em]x^2-4x+8 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}-4x+8 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
This page was created using
Polynomial Equations Solver