$$(x-2)(x+2) = 0$$
Answer
$$ \begin{matrix}x_1 = 2 & x_2 = -2 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x-2)(x+2) &= 0&& \text{simplify left side} \\[1 em]x^2+2x-2x-4 &= 0&& \\[1 em]x^2+2x-2x-4 &= 0&& \\[1 em]x^2-4 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}-4 = 0 $ is a quadratic equation.
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