$$(x-3)(2+3x-5) = 0$$
Answer
$$ \begin{matrix}x_1 = 1 & x_2 = 3 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x-3)(2+3x-5) &= 0&& \text{simplify left side} \\[1 em](x-3)(3x-3) &= 0&& \\[1 em]3x^2-3x-9x+9 &= 0&& \\[1 em]3x^2-12x+9 &= 0&& \\[1 em] \end{aligned} $$
$ 3x^{2}-12x+9 = 0 $ is a quadratic equation.
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