$$\frac{x^4+x^3-2x^2+5x-12}{x+2} = 0$$
Answer
$$ \begin{matrix}x_1 = 1.52854 & x_2 = -2.84359 & x_3 = 0.15753+1.65409i \\[1 em] x_4 = 0.15753-1.65409i & \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} \frac{x^4+x^3-2x^2+5x-12}{x+2} &= 0&& \text{multiply ALL terms by } \color{blue}{ x+2 }. \\[1 em](x+2)\frac{x^4+x^3-2x^2+5x-12}{x+2} &= (x+2)\cdot0&& \text{cancel out the denominators} \\[1 em]x^4+x^3-2x^2+5x-12 &= 0&& \\[1 em] \end{aligned} $$
This polynomial has no rational roots that can be found using Rational Root Test.
Roots were found using quartic formulas
This page was created using
Polynomial Equations Solver