$$(x^3+4)(x^3+1) = 0$$
Answer
$$ \begin{matrix}x_1 = -1 & x_2 = -1.5874 & x_3 = 0.5+0.86603i \\[1 em] x_4 = 0.5-0.86603i & x_5 = 0.7937+1.37473i & x_6 = 0.7937-1.37473i \end{matrix} $$
Explanation
$$ \begin{aligned} (x^3+4)(x^3+1) &= 0&& \text{simplify left side} \\[1 em]x^6+x^3+4x^3+4 &= 0&& \\[1 em]x^6+5x^3+4 &= 0&& \\[1 em] \end{aligned} $$
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