$$(w+1)(w-2) = 0$$
Answer
$$ \begin{matrix}w_1 = -1 & w_2 = 2 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (w+1)(w-2) &= 0&& \text{simplify left side} \\[1 em]w^2-2w+w-2 &= 0&& \\[1 em]w^2-w-2 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}-x-2 = 0 $ is a quadratic equation.
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