$$(v+3)(v-2) = 0$$
Answer
$$ \begin{matrix}v_1 = 2 & v_2 = -3 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (v+3)(v-2) &= 0&& \text{simplify left side} \\[1 em]v^2-2v+3v-6 &= 0&& \\[1 em]v^2+v-6 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}+x-6 = 0 $ is a quadratic equation.
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