$$(u-1)(2u+3) = 0$$
Answer
$$ \begin{matrix}u_1 = 1 & u_2 = -\dfrac{ 3 }{ 2 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (u-1)(2u+3) &= 0&& \text{simplify left side} \\[1 em]2u^2+3u-2u-3 &= 0&& \\[1 em]2u^2+u-3 &= 0&& \\[1 em] \end{aligned} $$
$ 2x^{2}+x-3 = 0 $ is a quadratic equation.
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