$$(s+2)(4s-2) = 0$$
Answer
$$ \begin{matrix}s_1 = \dfrac{ 1 }{ 2 } & s_2 = -2 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (s+2)(4s-2) &= 0&& \text{simplify left side} \\[1 em]4s^2-2s+8s-4 &= 0&& \\[1 em]4s^2+6s-4 &= 0&& \\[1 em] \end{aligned} $$
$ 4x^{2}+6x-4 = 0 $ is a quadratic equation.
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