$$(s+1)(s+2) = 0$$
Answer
$$ \begin{matrix}s_1 = -1 & s_2 = -2 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (s+1)(s+2) &= 0&& \text{simplify left side} \\[1 em]s^2+2s+s+2 &= 0&& \\[1 em]s^2+3s+2 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}+3x+2 = 0 $ is a quadratic equation.
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