$$(s-9)(s-1) = 0$$
Answer
$$ \begin{matrix}s_1 = 1 & s_2 = 9 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (s-9)(s-1) &= 0&& \text{simplify left side} \\[1 em]s^2-s-9s+9 &= 0&& \\[1 em]s^2-10s+9 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}-10x+9 = 0 $ is a quadratic equation.
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