$$(n+2)(n-3) = 0$$
Answer
$$ \begin{matrix}n_1 = -2 & n_2 = 3 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (n+2)(n-3) &= 0&& \text{simplify left side} \\[1 em]n^2-3n+2n-6 &= 0&& \\[1 em]n^2-n-6 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}-x-6 = 0 $ is a quadratic equation.
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