$$\frac{h^3-3h^2-10h}{h+2} = 0$$
Answer
$$ \begin{matrix}h_1 = 0 & h_2 = -2 & h_3 = 5 \end{matrix} $$
Explanation
$$ \begin{aligned} \frac{h^3-3h^2-10h}{h+2} &= 0&& \text{multiply ALL terms by } \color{blue}{ h+2 }. \\[1 em](h+2)\frac{h^3-3h^2-10h}{h+2} &= (h+2)\cdot0&& \text{cancel out the denominators} \\[1 em]h^3-3h^2-10h &= 0&& \\[1 em] \end{aligned} $$
In order to solve $ \color{blue}{ x^{3}-3x^{2}-10x = 0 } $, first we need to factor our $ x $.
$$ x^{3}-3x^{2}-10x = x \left( x^{2}-3x-10 \right) $$$ x = 0 $ is a root of multiplicity $ 1 $.
The remaining roots can be found by solving equation $ x^{2}-3x-10 = 0$.
$ x^{2}-3x-10 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
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