$$(f+4)^2 = 0$$
Answer
$$ f = -4 $$
Explanation
$$ \begin{aligned} (f+4)^2 &= 0&& \text{simplify left side} \\[1 em]f^2+8f+16 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}+8x+16 = 0 $ is a quadratic equation.
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