$$(d-2)(4d+1) = 0$$
Answer
$$ \begin{matrix}d_1 = -\dfrac{ 1 }{ 4 } & d_2 = 2 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (d-2)(4d+1) &= 0&& \text{simplify left side} \\[1 em]4d^2+d-8d-2 &= 0&& \\[1 em]4d^2-7d-2 &= 0&& \\[1 em] \end{aligned} $$
$ 4x^{2}-7x-2 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
This page was created using
Polynomial Equations Solver