$$a^2-3+2a^2-4a+4 = 0$$
Answer
$$ \begin{matrix}a_1 = 1 & a_2 = \dfrac{ 1 }{ 3 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} a^2-3+2a^2-4a+4 &= 0&& \text{simplify left side} \\[1 em]3a^2-4a+1 &= 0&& \\[1 em] \end{aligned} $$
$ 3x^{2}-4x+1 = 0 $ is a quadratic equation.
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