$$9x^2-5x+2x^2-7 = 0$$
Answer
$$ \begin{matrix}x_1 = \dfrac{ 5 }{ 22 }-\dfrac{ 3 \sqrt{ 37}}{ 22 } & x_2 = \dfrac{ 5 }{ 22 }+\dfrac{ 3 \sqrt{ 37}}{ 22 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 9x^2-5x+2x^2-7 &= 0&& \text{simplify left side} \\[1 em]11x^2-5x-7 &= 0&& \\[1 em] \end{aligned} $$
$ 11x^{2}-5x-7 = 0 $ is a quadratic equation.
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