$$7b^2+b+9-(3b^2+2) = 0$$
Answer
$$ \begin{matrix}b_1 = -\dfrac{ 1 }{ 8 }+\dfrac{\sqrt{ 111 }}{ 8 }i & b_2 = -\dfrac{ 1 }{ 8 }-\dfrac{\sqrt{ 111 }}{ 8 }i \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 7b^2+b+9-(3b^2+2) &= 0&& \text{simplify left side} \\[1 em]7b^2+b+9-3b^2-2 &= 0&& \\[1 em]4b^2+b+7 &= 0&& \\[1 em] \end{aligned} $$
$ 4x^{2}+x+7 = 0 $ is a quadratic equation.
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