$$(5v+4)(3v-6) = 0$$
Answer
$$ \begin{matrix}v_1 = 2 & v_2 = -\dfrac{ 4 }{ 5 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (5v+4)(3v-6) &= 0&& \text{simplify left side} \\[1 em]15v^2-30v+12v-24 &= 0&& \\[1 em]15v^2-18v-24 &= 0&& \\[1 em] \end{aligned} $$
$ 15x^{2}-18x-24 = 0 $ is a quadratic equation.
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