$$(\frac{5}{3}x+4)(\frac{5}{3}x+4) = 0$$
Answer
$$ x = -\frac{ 12 }{ 5 } $$
Explanation
$$ \begin{aligned} (\frac{5}{3}x+4)(\frac{5}{3}x+4) &= 0&& \text{simplify left side} \\[1 em](\frac{5x}{3}+4)(\frac{5x}{3}+4) &= 0&& \\[1 em]\frac{5x+12}{3}\frac{5x+12}{3} &= 0&& \\[1 em]\frac{25x^2+120x+144}{9} &= 0&& \text{multiply ALL terms by } \color{blue}{ 9 }. \\[1 em]9 \cdot \frac{25x^2+120x+144}{9} &= 9\cdot0&& \text{cancel out the denominators} \\[1 em]25x^2+120x+144 &= 0&& \\[1 em] \end{aligned} $$
$ 25x^{2}+120x+144 = 0 $ is a quadratic equation.
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