$$(4x+7)(4x-7) = 0$$
Answer
$$ \begin{matrix}x_1 = \dfrac{ 7 }{ 4 } & x_2 = -\dfrac{ 7 }{ 4 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (4x+7)(4x-7) &= 0&& \text{simplify left side} \\[1 em]16x^2-28x+28x-49 &= 0&& \\[1 em]16x^2-28x+28x-49 &= 0&& \\[1 em]16x^2-49 &= 0&& \\[1 em] \end{aligned} $$
$ 16x^{2}-49 = 0 $ is a quadratic equation.
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