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$$(4x+4)(3x-1) = 0$$
Answer
$$ \begin{matrix}x_1 = -1 & x_2 = \dfrac{ 1 }{ 3 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (4x+4)(3x-1) &= 0&& \text{simplify left side} \\[1 em]12x^2-4x+12x-4 &= 0&& \\[1 em]12x^2+8x-4 &= 0&& \\[1 em] \end{aligned} $$
$ 12x^{2}+8x-4 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
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