$$(4x-3)(3x-4) = 0$$
Answer
$$ \begin{matrix}x_1 = \dfrac{ 3 }{ 4 } & x_2 = \dfrac{ 4 }{ 3 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (4x-3)(3x-4) &= 0&& \text{simplify left side} \\[1 em]12x^2-16x-9x+12 &= 0&& \\[1 em]12x^2-25x+12 &= 0&& \\[1 em] \end{aligned} $$
$ 12x^{2}-25x+12 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
This page was created using
Polynomial Equations Solver