$$(4p+2)(4p-2) = 0$$
Answer
$$ \begin{matrix}p_1 = \dfrac{ 1 }{ 2 } & p_2 = -\dfrac{ 1 }{ 2 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (4p+2)(4p-2) &= 0&& \text{simplify left side} \\[1 em]16p^2-8p+8p-4 &= 0&& \\[1 em]16p^2-8p+8p-4 &= 0&& \\[1 em]16p^2-4 &= 0&& \\[1 em] \end{aligned} $$
$ 16x^{2}-4 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
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