$$4j\cdot3+9j\cdot2+3j+2j\cdot3+9j\cdot2+4j+6 = 0\cdot0$$
Answer
$$ j = -\frac{6}{61} $$
Explanation
$$ \begin{aligned} 4j\cdot3+9j\cdot2+3j+2j\cdot3+9j\cdot2+4j+6 &= 0\cdot0&& \text{simplify left and right hand side} \\[1 em]12j+18j+3j+6j+18j+4j+6 &= 0&& \\[1 em]33j+28j+6 &= 0&& \\[1 em]61j+6 &= 0&& \text{ move the constants to the right } \\[1 em]61j &= -6&& \text{ divide both sides by $ 61 $ } \\[1 em]j &= -\frac{6}{61}&& \\[1 em] \end{aligned} $$
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