$$4j\cdot3+9j\cdot2+3j+(2j\cdot3+9j\cdot2+4j+6)\cdot0 = 0$$
Answer
$$ j = 0 $$
Explanation
$$ \begin{aligned} 4j\cdot3+9j\cdot2+3j+(2j\cdot3+9j\cdot2+4j+6)\cdot0 &= 0&& \text{simplify left side} \\[1 em]12j+18j+3j+(6j+18j+4j+6)\cdot0 &= 0&& \\[1 em]33j+(28j+6)\cdot0 &= 0&& \\[1 em]33j+0j+0 &= 0&& \\[1 em]33j &= 0&& \text{ divide both sides by $ 33 $ } \\[1 em]j &= \frac{0}{33}&& \\[1 em]j &= 0&& \\[1 em] \end{aligned} $$
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