$$(4h+5)(h-6) = 0$$
Answer
$$ \begin{matrix}h_1 = -\dfrac{ 5 }{ 4 } & h_2 = 6 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (4h+5)(h-6) &= 0&& \text{simplify left side} \\[1 em]4h^2-24h+5h-30 &= 0&& \\[1 em]4h^2-19h-30 &= 0&& \\[1 em] \end{aligned} $$
$ 4x^{2}-19x-30 = 0 $ is a quadratic equation.
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