$$(4d+4)(d+4) = 0$$
Answer
$$ \begin{matrix}d_1 = -1 & d_2 = -4 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (4d+4)(d+4) &= 0&& \text{simplify left side} \\[1 em]4d^2+16d+4d+16 &= 0&& \\[1 em]4d^2+20d+16 &= 0&& \\[1 em] \end{aligned} $$
$ 4x^{2}+20x+16 = 0 $ is a quadratic equation.
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