$$(3z+2)(-2z+4) = 0$$
Answer
$$ \begin{matrix}z_1 = 2 & z_2 = -\dfrac{ 2 }{ 3 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (3z+2)(-2z+4) &= 0&& \text{simplify left side} \\[1 em]-6z^2+12z-4z+8 &= 0&& \\[1 em]-6z^2+8z+8 &= 0&& \\[1 em] \end{aligned} $$
$ -6x^{2}+8x+8 = 0 $ is a quadratic equation.
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