$$ \begin{aligned} \frac{3x+17}{x-2} &= 0&& \text{multiply ALL terms by } \color{blue}{ x-2 }. \\[1 em](x-2)\frac{3x+17}{x-2} &= (x-2)\cdot0&& \text{cancel out the denominators} \\[1 em]3x+17 &= 0&& \text{ move the constants to the right } \\[1 em]3x &= -17&& \text{ divide both sides by $ 3 $ } \\[1 em]x &= -\frac{17}{3}&& \\[1 em] \end{aligned} $$
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