$$(3x+1)(x-4) = 0$$
Answer
$$ \begin{matrix}x_1 = -\dfrac{ 1 }{ 3 } & x_2 = 4 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (3x+1)(x-4) &= 0&& \text{simplify left side} \\[1 em]3x^2-12x+x-4 &= 0&& \\[1 em]3x^2-11x-4 &= 0&& \\[1 em] \end{aligned} $$
$ 3x^{2}-11x-4 = 0 $ is a quadratic equation.
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