$$(3x-2)(2x+7) = 0$$
Answer
$$ \begin{matrix}x_1 = \dfrac{ 2 }{ 3 } & x_2 = -\dfrac{ 7 }{ 2 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (3x-2)(2x+7) &= 0&& \text{simplify left side} \\[1 em]6x^2+21x-4x-14 &= 0&& \\[1 em]6x^2+17x-14 &= 0&& \\[1 em] \end{aligned} $$
$ 6x^{2}+17x-14 = 0 $ is a quadratic equation.
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