$$(3x-2)(2x-4) = 0$$
Answer
$$ \begin{matrix}x_1 = 2 & x_2 = \dfrac{ 2 }{ 3 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (3x-2)(2x-4) &= 0&& \text{simplify left side} \\[1 em]6x^2-12x-4x+8 &= 0&& \\[1 em]6x^2-16x+8 &= 0&& \\[1 em] \end{aligned} $$
$ 6x^{2}-16x+8 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
This page was created using
Polynomial Equations Solver