$$(3n+2)(n+3) = 0$$
Answer
$$ \begin{matrix}n_1 = -\dfrac{ 2 }{ 3 } & n_2 = -3 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (3n+2)(n+3) &= 0&& \text{simplify left side} \\[1 em]3n^2+9n+2n+6 &= 0&& \\[1 em]3n^2+11n+6 &= 0&& \\[1 em] \end{aligned} $$
$ 3x^{2}+11x+6 = 0 $ is a quadratic equation.
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