$$(3h-1)(3h+1) = 0$$
Answer
$$ \begin{matrix}h_1 = \dfrac{ 1 }{ 3 } & h_2 = -\dfrac{ 1 }{ 3 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (3h-1)(3h+1) &= 0&& \text{simplify left side} \\[1 em]9h^2+3h-3h-1 &= 0&& \\[1 em]9h^2+3h-3h-1 &= 0&& \\[1 em]9h^2-1 &= 0&& \\[1 em] \end{aligned} $$
$ 9x^{2}-1 = 0 $ is a quadratic equation.
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