$$(3b+4)(b+1) = 0$$
Answer
$$ \begin{matrix}b_1 = -1 & b_2 = -\dfrac{ 4 }{ 3 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (3b+4)(b+1) &= 0&& \text{simplify left side} \\[1 em]3b^2+3b+4b+4 &= 0&& \\[1 em]3b^2+7b+4 &= 0&& \\[1 em] \end{aligned} $$
$ 3x^{2}+7x+4 = 0 $ is a quadratic equation.
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