$$\frac{30x^2-96x+18}{15x+3} = 0$$
Answer
$$ \begin{matrix}x_1 = \dfrac{ 1 }{ 5 } & x_2 = 3 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} \frac{30x^2-96x+18}{15x+3} &= 0&& \text{multiply ALL terms by } \color{blue}{ 15x+3 }. \\[1 em](15x+3)\frac{30x^2-96x+18}{15x+3} &= (15x+3)\cdot0&& \text{cancel out the denominators} \\[1 em]30x^2-96x+18 &= 0&& \\[1 em] \end{aligned} $$
$ 30x^{2}-96x+18 = 0 $ is a quadratic equation.
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