$$(3-4x)\cdot(4+2x) = 0$$
Answer
$$ \begin{matrix}x_1 = -2 & x_2 = \dfrac{ 3 }{ 4 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (3-4x)\cdot(4+2x) &= 0&& \text{simplify left side} \\[1 em]12+6x-16x-8x^2 &= 0&& \\[1 em]-8x^2-10x+12 &= 0&& \\[1 em] \end{aligned} $$
$ -8x^{2}-10x+12 = 0 $ is a quadratic equation.
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