$$(3-2g)\cdot(7-g) = 0$$
Answer
$$ \begin{matrix}g_1 = \dfrac{ 3 }{ 2 } & g_2 = 7 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (3-2g)\cdot(7-g) &= 0&& \text{simplify left side} \\[1 em]21-3g-14g+2g^2 &= 0&& \\[1 em]2g^2-17g+21 &= 0&& \\[1 em] \end{aligned} $$
$ 2x^{2}-17x+21 = 0 $ is a quadratic equation.
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