$$(2y+4)^2 = 0$$
Answer
$$ y = -2 $$
Explanation
$$ \begin{aligned} (2y+4)^2 &= 0&& \text{simplify left side} \\[1 em]4y^2+16y+16 &= 0&& \\[1 em] \end{aligned} $$
$ 4x^{2}+16x+16 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
This page was created using
Polynomial Equations Solver