$$(2x+7)^2 = 0$$
Answer
$$ x = -\frac{ 7 }{ 2 } $$
Explanation
$$ \begin{aligned} (2x+7)^2 &= 0&& \text{simplify left side} \\[1 em]4x^2+28x+49 &= 0&& \\[1 em] \end{aligned} $$
$ 4x^{2}+28x+49 = 0 $ is a quadratic equation.
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