$$2x\cdot1(x+3) = 0$$
Answer
$$ \begin{matrix}x_1 = 0 & x_2 = -3 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 2x\cdot1(x+3) &= 0&& \text{simplify left side} \\[1 em]2x^2+6x &= 0&& \\[1 em] \end{aligned} $$
In order to solve $ \color{blue}{ 2x^{2}+6x = 0 } $, first we need to factor our $ x $.
$$ 2x^{2}+6x = x \left( 2x+6 \right) $$$ x = 0 $ is a root of multiplicity $ 1 $.
The second root can be found by solving equation $ 2x+6 = 0$.
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