$$(2x-6)(7x+1) = 0$$
Answer
$$ \begin{matrix}x_1 = -\dfrac{ 1 }{ 7 } & x_2 = 3 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (2x-6)(7x+1) &= 0&& \text{simplify left side} \\[1 em]14x^2+2x-42x-6 &= 0&& \\[1 em]14x^2-40x-6 &= 0&& \\[1 em] \end{aligned} $$
$ 14x^{2}-40x-6 = 0 $ is a quadratic equation.
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