$$(2x-4)^2+2(2x-4)+1 = 0$$
Answer
$$ x = \frac{ 3 }{ 2 } $$
Explanation
$$ \begin{aligned} (2x-4)^2+2(2x-4)+1 &= 0&& \text{simplify left side} \\[1 em]4x^2-16x+16+2(2x-4)+1 &= 0&& \\[1 em]4x^2-16x+16+4x-8+1 &= 0&& \\[1 em]4x^2-12x+8+1 &= 0&& \\[1 em]4x^2-12x+9 &= 0&& \\[1 em] \end{aligned} $$
$ 4x^{2}-12x+9 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
This page was created using
Polynomial Equations Solver