$$(2x-3)(5x+6) = 0$$
Answer
$$ \begin{matrix}x_1 = \dfrac{ 3 }{ 2 } & x_2 = -\dfrac{ 6 }{ 5 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (2x-3)(5x+6) &= 0&& \text{simplify left side} \\[1 em]10x^2+12x-15x-18 &= 0&& \\[1 em]10x^2-3x-18 &= 0&& \\[1 em] \end{aligned} $$
$ 10x^{2}-3x-18 = 0 $ is a quadratic equation.
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