$$(2x-1)(6x+3) = 0$$
Answer
$$ \begin{matrix}x_1 = \dfrac{ 1 }{ 2 } & x_2 = -\dfrac{ 1 }{ 2 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (2x-1)(6x+3) &= 0&& \text{simplify left side} \\[1 em]12x^2+6x-6x-3 &= 0&& \\[1 em]12x^2+6x-6x-3 &= 0&& \\[1 em]12x^2-3 &= 0&& \\[1 em] \end{aligned} $$
$ 12x^{2}-3 = 0 $ is a quadratic equation.
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