$$\frac{2x^3-4x+7}{x^2-4x} = 0$$
Answer
$$ \begin{matrix}x_1 = -1.94842 & x_2 = 0.97421+0.92046i & x_3 = 0.97421-0.92046i \end{matrix} $$
Explanation
$$ \begin{aligned} \frac{2x^3-4x+7}{x^2-4x} &= 0&& \text{multiply ALL terms by } \color{blue}{ x^2-4x }. \\[1 em](x^2-4x)\frac{2x^3-4x+7}{x^2-4x} &= (x^2-4x)\cdot0&& \text{cancel out the denominators} \\[1 em]2x^3-4x+7 &= 0&& \\[1 em] \end{aligned} $$
This polynomial has no rational roots that can be found using Rational Root Test.
Roots were found using qubic formulas.
This page was created using
Polynomial Equations Solver