$$(2c+3)(c-3) = 0$$
Answer
$$ \begin{matrix}c_1 = 3 & c_2 = -\dfrac{ 3 }{ 2 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (2c+3)(c-3) &= 0&& \text{simplify left side} \\[1 em]2c^2-6c+3c-9 &= 0&& \\[1 em]2c^2-3c-9 &= 0&& \\[1 em] \end{aligned} $$
$ 2x^{2}-3x-9 = 0 $ is a quadratic equation.
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