$$(25-x)(x-9) = 0$$
Answer
$$ \begin{matrix}x_1 = 9 & x_2 = 25 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (25-x)(x-9) &= 0&& \text{simplify left side} \\[1 em]25x-225-x^2+9x &= 0&& \\[1 em]-x^2+34x-225 &= 0&& \\[1 em] \end{aligned} $$
$ -x^{2}+34x-225 = 0 $ is a quadratic equation.
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