$$241 \cdot \frac{x^3}{3}-498x^2+596x-120 = 0$$
Answer
$$ \begin{matrix}x_1 = 0.25241 & x_2 = 1.26372 & x_3 = 4.68304 \end{matrix} $$
Explanation
$$ \begin{aligned} 241 \cdot \frac{x^3}{3}-498x^2+596x-120 &= 0&& \text{multiply ALL terms by } \color{blue}{ 3 }. \\[1 em]3\cdot241 \cdot \frac{x^3}{3}-3\cdot498x^2+3\cdot596x-3\cdot120 &= 3\cdot0&& \text{cancel out the denominators} \\[1 em]241x^3-1494x^2+1788x-360 &= 0&& \\[1 em] \end{aligned} $$
This polynomial has no rational roots that can be found using Rational Root Test.
Roots were found using qubic formulas.
This page was created using
Polynomial Equations Solver